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悬臂式钢板桩和板桩稳定性计算计算书

2023-07-06 来源:步旅网


悬臂式板桩和板桩稳定性计算计算书

一、编制依据

本计算书的编制参照《建筑基坑支护技术规程》(JGJ120-99),《土力学与地基基础》(清华大学出版社出版)等编制。

二、参数信息

重要性系数:1.00; 开挖深度度h:2.55m;

基坑外侧水位深度hwa:3.4m; 基坑内侧水位深度hwp:0.80m;桩嵌入土深度hd:4m; 基坑边缘外荷载形式:无荷载

悬臂板桩材料:20号槽钢; 弹性模量E:206000N/mm2;

强度设计值[fm]:205N/mm2; 桩间距bs:0.10m;

截面抵抗矩Wx:191.4cm3; 截面惯性矩Ix:1913.70cm4;

基坑土层参数:

序号 土名称 土厚度 坑壁土的重度 内摩擦角 内聚力 浮容重

(m) (kN/m3) (°) (kPa) (kN/m3)

1 粘性土 4.3 18.2 7.5 12.2 18.2

2 粘性土 2.1 18.3 5.6 11.8 18.3

3 粉土 2.2 18.6 17.3 4 粘性土 5.3 19.3 6.5 三、土压力计算

1、水平荷载

11.3 18.6

37 19.3

(1)、主动土压力系数:

Ka1=tan2(45°- φ1/2)= tan2(45-7.5/2)=0.769;

Ka2=tan2(45°- φ2/2)= tan2(45-7.5/2)=0.769;

Ka3=tan2(45°- φ3/2)= tan2(45-5.6/2)=0.822;

Ka4=tan2(45°- φ4/2)= tan2(45-17.3/2)=0.542;

(2)、土压力、地下水以及地面附加荷载产生的水平荷载:

第1层土:0 ~ 3.4米;

σa1上 = P1Ka1-2C1Ka10.5 = 0×0.769-2×12.2×0.7690.5 = -21.398kN/m;

σa1下 = (γ1h1+P1)Ka1-2C1Ka10.5 = [18.2×3.4+0]×0.769-2×12.2×0.7690.5 =

26.193kN/m;

第2层土:3.4 ~ 4.3米;

H2' = ∑γihi/γ2 = 61.88/18.2 = 3.4;

σa2上 = [γ2H2'+P1+P2a2/(a2+2l2)]Ka2-2C2Ka20.5 =

[18.2×3.4+0+0]×0.769-2×12.2×0.7690.5 = 26.193kN/m2;

σa2下 = [γ2H2'+P1+P2a2/(a2+2l2)]Ka2-2C2Ka20.5+γ'h2Ka2+0.5γwh22 =

[18.2×3.4+0+0]×0.769-2×12.2×0.7690.5+18.2×0.9×0.769+0.5×10×0.92 = 42.841kN/m2;

第3层土:4.3 ~ 6.4米;

H3' = H2' = 3.4;

σa3上 = [γ3H3'+P1+P2a2/(a2+2l2)]Ka3-2C3Ka30.5+γ'h3Ka3+0.5γwh32 =

[18.3×3.4+0+0]×0.822-2×11.8×0.8220.5+18.3×0.9×0.822+0.5×10×0.92 = 47.349kN/m2;

σa3下 = [γ3H3'+P1+P2a2/(a2+2l2)]Ka3-2C3Ka30.5+γ'h3Ka3+0.5γwh32 =

[18.3×3.4+0+0]×0.822-2×11.8×0.8220.5+18.3×3×0.822+0.5×10×32 = 119.895kN/m2;

第4层土:6.4 ~ 6.55米;

H4' = H3' = 3.4;

σa4上 = [γ4H4'+P1+P2a2/(a2+2l2)]Ka4-2C4Ka40.5+γ'h4Ka4+0.5γwh42 =

[18.6×3.4+0+0]×0.542-2×11.3×0.5420.5+18.6×3×0.542+0.5×10×32 =

92.837kN/m2;

σa4下 = [γ4H4'+P1+P2a2/(a2+2l2)]Ka4-2C4Ka40.5+γ'h4Ka4+0.5γwh42 =

[18.6×3.4+0+0]×0.542-2×11.3×0.5420.5+18.6×3.15×0.542+0.5×10×3.152 = 98.961kN/m2;

(3)、水平荷载:

Z0=(σa1下×h1)/(σa1上+ σa1下)=(26.193×3.4)/(21.398×26.193)=1.871m;

第1层土:

Ea1=0.5×Z0×σa1下=0.5×1.871×26.193=24.507kN/m;

作用位置:ha1=Z0/3+∑hi=1.871/3+3.15=3.774m;

第2层土:

Ea2=h2×(σa2上+σa2下)/2=0.9×(26.193+42.841)/2=31.065kN/m;

作用位置:ha2=h2(2σa2上+σa2下)/(3σa2上+3σa2下)+∑

hi=0.9×(2×26.193+42.841)/(3×26.193+3×42.841)+2.25=2.664m;

第3层土:

Ea3=h3×(σa3上+σa3下)/2=2.1×(47.349+119.895)/2=175.606kN/m;

作用位置:ha3=h3(2σa3上+σa3下)/(3σa3上+3σa3下)+∑

hi=2.1×(2×47.349+119.895)/(3×47.349+3×119.895)+0.15=1.048m;

第4层土:

Ea4=h4×(σa4上+σa4下)/2=0.15×(92.837+98.961)/2=14.385kN/m;

作用位置:ha4=h4(2σa4上+σa4下)/(3σa4上+3σa4下)+∑

hi=0.15×(2×92.837+98.961)/(3×92.837+3×98.961)+0=0.074m;

土压力合力:Ea= ΣEai= 24.507+31.065+175.606+14.385=245.563kN/m;

合力作用点:ha= ΣhiEai/Ea=

(24.507×3.774+31.065×2.664+175.606×1.048+14.385×0.074)/245.563=1.468m;

2、水平抗力计算

(1)、被动土压力系数:

Kp1=tan2(45°+ φ1/2)= tan2(45+7.5/2)=1.3;

Kp2=tan2(45°+ φ2/2)= tan2(45+7.5/2)=1.3;

Kp3=tan2(45°+ φ3/2)= tan2(45+5.6/2)=1.216;

Kp4=tan2(45°+ φ4/2)= tan2(45+17.3/2)=1.846;

(2)、土压力、地下水产生的水平荷载:

第1层土:2.55 ~ 3.35米;

σp1上 = 2C1Kp10.5 = 2×12.2×1.30.5 = 27.823kN/m;

σp1下 = γ1h1Kp1+2C1Kp10.5 = 18.2×0.8×1.3+2×12.2×1.30.5 = 46.754kN/m;

第2层土:3.35 ~ 4.3米;

H2' = ∑γihi/γ2 = 14.56/18.2 = 0.8;

σa2上 = γ2H2'Kp2+2C2Kp20.5 = 18.2×0.8×1.3+2×12.2×1.30.5 = 46.754kN/m;

σa2下 = γ2H2'Kp2+2C2Kp20.5+γ'h2Kp2+0.5γwh22 =

18.2×0.8×1.3+2×12.2×1.30.5+18.2×0.95×1.3+0.5×10×0.952 = 73.748kN/m;

第3层土:4.3 ~ 6.4米;

H3' = H2' = 0.8;

σp3上 = [γ3H3']Kp3+2C3Kp30.5+γ'h3Kp3+0.5γwh32 =

[18.3×0.8]×1.216+2×11.8×1.2160.5+18.3×0.95×1.216+0.5×10×0.952 = 69.491kN/m;

σp3下 = [γ3H3']Kp3+2C3Kp30.5+γ'h3Kp3+0.5γwh32 =

[18.3×0.8]×1.216+2×11.8×1.2160.5+18.3×3.05×1.216+0.5×10×3.052 = 158.232kN/m;

第4层土:6.4 ~ 6.55米;

H4' = H3' = 0.8;

σp4上 = [γ4H4']Kp4+2C4Kp40.5+γ'h4Kp4+0.5γwh42 =

[18.6×0.8]×1.846+2×11.3×1.8460.5+18.6×3.05×1.846+0.5×10×3.052 = 209.448kN/m;

σp4下 = [γ4H4']Kp4+2C4Kp40.5+γ'h4Kp4+0.5γwh42 =

[18.6×0.8]×1.846+2×11.3×1.8460.5+18.6×3.2×1.846+0.5×10×3.22 = 219.287kN/m;

(3)、水平荷载:

第1层土:

Ep1=h1×(σp1上+σp1下)/2=0.8×(27.823+46.754)/2=29.831kN/m;

作用位置:hp1=h1(2σp1上+σp1下)/(3σp1上+3σp1下)+∑

hi=0.8×(2×27.823+46.754)/(3×27.823+3×46.754)+3.2=3.566m;

第2层土:

Ep2=h2×(σp2上+σp2下)/2=0.95×(46.754+73.748)/2=57.239kN/m;

作用位置:hp2=h2(2σp2上+σp2下)/(3σp2上+3σp2下)+∑

hi=0.95×(2×46.754+73.748)/(3×46.754+3×73.748)+2.25=2.69m;

第3层土:

Ep3=h3×(σp3上+σp3下)/2=2.1×(69.491+158.232)/2=239.109kN/m;

作用位置:hp3=h3(2σp3上+σp3下)/(3σp3上+3σp3下)+∑

hi=2.1×(2×69.491+158.232)/(3×69.491+3×158.232)+0.15=1.064m;

第4层土:

Ep4=h4×(σp4上+σp4下)/2=0.15×(209.448+219.287)/2=32.155kN/m;

作用位置:hp4=h4(2σp4上+σp4下)/(3σp4上+3σp4下)+∑

hi=0.15×(2×209.448+219.287)/(3×209.448+3×219.287)+0=0.074m;

土压力合力:Ep= ΣEpi= 29.831+57.239+239.109+32.155=358.334kN/m;

合力作用点:hp= ΣhiEpi/Ep=

(29.831×3.566+57.239×2.69+239.109×1.064+32.155×0.074)/358.334=1.443m;

四、验算嵌固深度是否满足要求

根据《建筑基坑支护技术规程》(JGJ 120-99)的要求,验证所假设的hd是否满足公式;

hp∑Epj - 1.2γ0haEai ≥ 0

1.44×358.33-1.2×1.00×1.47×245.56=84.59;

满足公式要求!

五、抗渗稳定性验算

根据《建筑基坑支护技术规程》(JGJ 120-99)要求,此时可不进行抗渗稳定性验算!

六、结构计算

1、结构弯矩计算

弯矩图(kN·m)

变形图(m)

悬臂式支护结构弯矩Mc=15.23kN·m;

最大挠度为:0.03m;

2、截面弯矩设计值确定:

M=1.25γ0Mc

截面弯矩设计值M=1.25×1.00×15.23=19.04;

γ0----为重要性系数,按照《建筑基坑支护技术规程》(JGJ120-99),表3.1.3可以选定。

七、截面承载力计算

1、材料的强度计算:

σmax=M/(γxWx)

γx-----塑性发展系数,对于承受静力荷载和间接承受动力荷载的构件,偏于安全考虑,可取为1.0;

Wx-----材料的截面抵抗矩: 191.40 cm3

σ-3

max=M/(γx×Wx)=19.04/(1.0×191.40×10)=99.47 MPa

σmax=99.47 MPa<[fm]=205.00 MPa;

经比较知,材料强度满足要求。

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